Electric and Magnetic Fields

Hi Guys! today we started class with the questions given by Miss Kozoriz yesterday from the duck book.

75. d=5cm/100=0.05m
E=5.10^3 N/C
V=E.d=2.5.10^2 V

76.
a) F=E.q=5.0.10^-4N
b) Ek=EP
EP=qV
V=Ed
V=(50)(1.0)=50V
EP=(10^-5)(50)=5.0.10^-4J
c) m=2KE/v.v=1.6.10^-12 kg

77. delta E= E2-E1=k q1q2/R2-k q1q2/R1=-2.08.10^-19 J

79.
a) q=W/V=1.8.10^-3 C
# of electrons=1.10^16 electrons
b)v2= under root qV/m=6.6.10^-23

80.
a)a=3.0.10^10 m/s. square
b)v=1.2.10^-15 J

81. R=1.9.10^-14m

82.
a)delta dh=0.00025m
b)v=6.0.10^6m/s

90.
a) Fe=Fg
Fe=mg
E=v/d
q=Fe/E
=mg/v/d
=mgd/v
=4.2.10^-19C

91.
a)v= under root 2qv/m=1.2.10^7m/s
b)v=under root 2deltaEe/3m=7.26.10^6m/s

                               As we've test tomorrow so we reviewed all the topics about Magnetic and Electric Fields. We have test tomorrow on Electric and Magnetic Fields so be prepared and good luck

Hi everyone,

                      Today we did lab and before that Ms.Kozoriz discussed WORK  "which is defined as the integral of force over a distance of displacement." 

        Work=Force.Distance

         w=f.d

Its unit is joule. POWER "it is the time rate at which work is done"

           Power=Work done/Time

           p=w/t

Its unit is watt. Then we did lab on work and power. Also we got a chapter 10 study guide on Energy and Power. Lab worksheet on centripetal force and problem 4 and 5 were marked and were given back to us. Thats all we did today. Hope this post will help those who missed the class.

                                                        GOOD LUCK

Projectile Motion

Hi Dear Classmates,

                                      today Ms.Kozoriz returned our chapter 6 REINFORCEMENT. After that Ms.Kozoriz solved the problems 1-4 from chapter 6 REVIEW the solution is:

1. horizontal velocity vh=800m/s

horizontal distance dh=180m

time t=dh/vh

t=180m/800m/s

t=0.225s

vertical distance dv=1/2g.tsquare

dv=1/2.9.8m/secsquare.0.225s.0.225s

dv=0.25m

2.dv=8.0m

dh=10.0m

t=under root 2dv/g

t=under root 2.8.0m/9.8m/s

t=1.27s

vh=dh/t

vh=10m/1.27s

vh=7.8m/s

3.

    a.    vh=45m/s

theta=45 degrees

vh=cos45 degree.45m/s=31.8m/s

vv=sin45 degrees.45m/s=31.8m/s

t=2vv/g

t=2.31.8m/s/9.8m/secsquare

t=6.48s

   b.  dh=vh.t

dh=31.8m/s.6.48s

dh=206.06m

4.

    a.  v=8m/s

theta=30 degrees

vh=cos30 degrees.8m/s=6.928m/s

vv=sin30 degrees.8m/s=4m/s

t=2vv/g

t=2.4m/s/9.8m/secsquare=0.81s

   b.  dv=v2 square-v1 square/2g

dv=o-16m/s/2.-9.8

dv=-16m/s/-19.6

dv=0.82m

    c.  dh=vh.t

dh=6.928m/s.0.81s

dh=5.61m

                   the remaining 5 problems are related to our next topics so we'll do them in future.

We also solved the green book's 2-7 problems. The solutions are:

2.vh=8m/s

dv=78.4m

t=under root 2dv/g

t=4s

dh=vh.t

dh=8.4

dh=32m

3.

   a.    t=under root vv/g

t=under root 1.225/9.8

t=under root .25

t=.5 s

    b.  vh=dh/t

vh=0.40/.5

vh=0.800m/s

4. vh=2.8m/s

t=2.6s

dv=?

dh=vh.t

dh=2.8.2.6

dh=7.26m

dv=1/2gtsquare

dv=33.1m

5.

   a.  dv=1001m

vh=125km/hr=34.7m/s

t=under root 2 dv/g

t=14.3s

   b.dh=vh.t

dh=34.7.14.3

dh=496.21m

6.dv=61m

dh=23m

vh=3m/s

t=under root 2dv/g

t=3.52s

vh=dh/t

vh=6.51

7. vy=vyt+1/2gt square  since vy=o

t=under root 2y/g

t=under root 2.-0.32/-9.8

t=0.26

x=vxt=12.4m/s . 0.26s

=3.2m

          Then we revised the formulas for projectile quiz. We did quiz about projectile. Thats all we did today and TOMORROW WE'LL HAVE A TEST ON MOMENTUM and Projectile Motion so be prepared.

      

                        BEST OF LUCK