Showing posts with label Nageena. Show all posts
Showing posts with label Nageena. Show all posts

Sunday, December 12, 2010

Electric and Magnetic Fields

Hey Classmates we started from "Moving Charges Worksheet" 
and we went over problem 8 to 11 in the class.

8.v=2.1 . 10^5 m/s
   f=5.6 . 10^-13 N
   B=f/qv
   B=5.6 . 10^-13/(1.6 . 10^-19)(2.1 . 10^5)
   B=16.6T[left]

9.v=8.6 . 10^4m/s
    B=1.2T
    F=?
    F=Bqv
    F=(1.2 )(1.6 . 10^-19)(8.6 . 10^)
    F=1.7 . 10^-14N[E] 

10.v=5.0 . 10^5m/s
     F=4.0 . 10^-6N
     B=F/qv
     B=4.0 . 10^-6/(1.6 . 10^-19)(5.0 . 10^5)
     B=5. . 10^7T [out of the page]

11.v=2.0 . 10^6m/s
    B=5.0 . 10^-2T
    F=4.8 . 10^-14N
    q=?
    q=F/Bv
    q=4.0 . 10^-14/(5.0 . 10^-2)(2.0 . 10^6)
    q=4.8 . 10^-19C

Miss Kozoriz explain a bit The Mass of an Electron, we read the Green book from page 536-541 for some basic formulas.
We got home work for the Worksheet "Moving Charges" for problems 12-16 and Review Chapter 27. And we have test on Tuesday. Have a nice weekend and prepare for the test.

Monday, December 6, 2010

Hey classmates, today we started with Electric Potential 33-2 worksheet. We hand in our lab sheet and then Ms.Kozoriz explained Electron Volt and Equipotential line. We also discussed "Potential Energy and Kinetic Energy between two charged plates" worksheet. After  that we got 3 worksheet to work on; Appendix 2 -Fields (Illustrative examples), The physics of Cathode Ray Tube and Electric Potential. We'll hand these worksheets on wednesday. Thats all what we did in class.
  Have a great evening!

Monday, November 1, 2010

Hello Everyone, today we went over the answers of chapter 10 Study Guide page 56 and 57 which are given below;
    
MATCHING:
1. f
2. c
3. a
4. b
5. d
6. e

MCQ'S:
7. a
8. b
9. b
10. a
11. a
12. a
  
For each of the situation shown, write the letter next to the number of the correct expression.
13. B,E,F
14. A,D
15. C

ANSWERS:
16. 30N
17. 0.5m
18. work done
19. 3J

MATCH THE FOLLOWING:
20. a 
21. c
22. e
23. b
24. d
         Those who were absent on Thursday did the lab and the other students were working on chapter 10 Transparency 10-1 (Force, Work and Distance). Ms.Kozoriz helped us solving those questions, the answers are;

1. 150N
2. 8.0m
3. 0-150N as force increases the object moves 3.0m. Between 3-6m a constant of 150N is applied to object. For last 4m force is upward from 150N to 250N.
4. w=f.d
5. w=f.d
w=150N.2m
w=300N.m(J)
          Then Ms.Kzoriz gave us a helpful lecture on Kinetic Energy and Gravitational Potentional Energy. After we performed an experiment on Conservation Of Energy with 3 balls of different sizes and a meterstick. We also get a chapter 11 Transparency11-3 Worksheet in which we have to answer 7 questions.
                      Thats all we did today and also we handed in our lab worksheet on work and power. Unfortunately, tomorrow we dont have a Physics period because its half day. 
                                                                                                              Have a great day,
                                                                                                              Nageena.

Thursday, October 14, 2010

Hello everyone,
                        Today we started with chapter 6 study guide which is about motion in two dimension. The answers are 
VOCABULARY REVIEW
 1. centripetal force
 2. projectile
 3. uniform circular motion
 4. centripetal acceleration
 5. trajectory

                                         PROJECTILE  MOTION
1. To an observer at position A the ball would appear moving straight up and straight down.

2. To an observer at position B the ball would appear moving in straight line.

3. To an observer at position C the ball would appear as an arc (parabola).

4. Throughout its flight,a projectile is constantly being accelerated toward the ground. Vertical vector shrinks until it reaches the top of its flight and then it increases as it approaches the ground. The horizontal velocity vector remains constant throughout its flight. Vertical vector is under the influence of gravity and horizontal vector has no net external force acting on it.

5. Neither rock lands first. Both rocks hit the ground at same time. This is occuring because both are under the same external force that is gravity(g).

6. Time t = ?
     d =8500m
      g=9.8m/s
      t=  2d/g
      t=2.8500m/9.8m/s
      t=1734.69
      t=41.64s      answer 

7. Vertical velocity v=?
     a=vf-vi/t
     v=a.t
     v=9.8m/s(42s)
     v=410m/s

8. dh=?
    Horizontal velocity v=483km/hr=134m/s 
    d=v.t
    d=483m/s.42s
    d=5600m

       Ms.Kzoriz wrote the answers for transparency sheet 6-1 and 2 on whiteboard. The answers for 6-1 are:
1. The magnitude of the ball's velocity vector is smallest at its maximum height.

2. Equal in magnitude but opposite in direction.

3. Equal in magnitude and in direction.

4. The line for horizontal position is a straight line and for vertical position its an arc.

        The answers for 6-2 are:
1. Same vertical vector at each point.

2. Both balls fall at same acceleration.

3. Horizontal motion of red ball does not affect its vertical motion.

4. Vertical interval is greater near the bottom of diagram. Since the time interval between each two picture is same, vertical vector of ball must have increased.

5. Horizontal interval between each two pictures of ball are identical. Since the intervals represent identical time periods. Horizontal vectors of the ball must be constant.

            Ms.Kozoriz talked about upwardly launched projectiles and we started to solve the problems on page 11 PROJECTILE MOTION 2. While doing problems we enjoyed a song Harry the Human Cannonball. Thats all we did in class today. One other important thing is ourshort  momentum test will be on Tuesday not on Monday.

      Its my first blog so if you guys found any mistakes sorry about that.